3t^2-6t-200=0

Solution for 3t^2-6t-200=0 equation:

3t^2-6t-200=0

a = 3; b = -6; c = -200;
Δ = b2-4ac
Δ = -62-4·3·(-200)
Δ = 2436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2436}=\sqrt{4*609}=\sqrt{4}*\sqrt{609}=2\sqrt{609}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{609}}{2*3}=\frac{6-2\sqrt{609}}{6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{609}}{2*3}=\frac{6+2\sqrt{609}}{6}
$